1016 lines
25 KiB
C
1016 lines
25 KiB
C
#include <stdlib.h>
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#include <stdio.h>
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#include "main.h"
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#include "misc.h"
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#include "funcs.h"
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/* hack to ignore GCC Unused Result */
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#define IGNORE(r) do{if(r){}}while(0)
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/* I/O ROUTINES (SPEAK, PSPEAK, RSPEAK, SETPRM, GETIN, YES) */
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#undef SPEAK
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void fSPEAK(long N) {
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long BLANK, CASE, I, K, L, NEG, NPARMS, PARM, PRMTYP, STATE;
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/* PRINT THE MESSAGE WHICH STARTS AT LINES(N). PRECEDE IT WITH A BLANK LINE
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* UNLESS BLKLIN IS FALSE. */
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if(N == 0)return;
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BLANK=BLKLIN;
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K=N;
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NPARMS=1;
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L10: L=IABS(LINES[K])-1;
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K=K+1;
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LNLENG=0;
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LNPOSN=1;
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STATE=0;
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/* 20 */ for (I=K; I<=L; I++) {
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L20: PUTTXT(LINES[I],STATE,2,I);
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} /* end loop */
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LNPOSN=0;
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L30: LNPOSN=LNPOSN+1;
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L32: if(LNPOSN > LNLENG) goto L40;
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if(INLINE[LNPOSN] != 63) goto L30;
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{long x = LNPOSN+1; PRMTYP=INLINE[x];}
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/* 63 IS A "%"; THE NEXT CHARACTER DETERMINE THE TYPE OF PARAMETER: 1 (!) =
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* SUPPRESS MESSAGE COMPLETELY, 29 (S) = NULL IF PARM=1, ELSE 'S' (OPTIONAL
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* PLURAL ENDING), 33 (W) = WORD (TWO 30-BIT VALUES) WITH TRAILING SPACES
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* SUPPRESSED, 22 (L) OR 31 (U) = WORD BUT MAP TO LOWER/UPPER CASE, 13 (C) =
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* WORD IN LOWER CASE WITH FIRST LETTER CAPITALISED, 30 (T) = TEXT ENDING
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* WITH A WORD OF -1, 65-73 (1-9) = NUMBER USING THAT MANY CHARACTERS,
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* 12 (B) = VARIABLE NUMBER OF BLANKS. */
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if(PRMTYP == 1)return;
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if(PRMTYP == 29) goto L320;
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if(PRMTYP == 30) goto L340;
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if(PRMTYP == 12) goto L360;
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if(PRMTYP == 33 || PRMTYP == 22 || PRMTYP == 31 || PRMTYP == 13) goto
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L380;
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PRMTYP=PRMTYP-64;
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if(PRMTYP < 1 || PRMTYP > 9) goto L30;
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SHFTXT(LNPOSN+2,PRMTYP-2);
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LNPOSN=LNPOSN+PRMTYP;
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PARM=IABS(PARMS[NPARMS]);
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NEG=0;
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if(PARMS[NPARMS] < 0)NEG=9;
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/* 390 */ for (I=1; I<=PRMTYP; I++) {
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LNPOSN=LNPOSN-1;
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INLINE[LNPOSN]=MOD(PARM,10)+64;
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if(I == 1 || PARM != 0) goto L390;
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INLINE[LNPOSN]=NEG;
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NEG=0;
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L390: PARM=PARM/10;
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} /* end loop */
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LNPOSN=LNPOSN+PRMTYP;
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L395: NPARMS=NPARMS+1;
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goto L32;
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L320: SHFTXT(LNPOSN+2,-1);
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INLINE[LNPOSN]=55;
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if(PARMS[NPARMS] == 1)SHFTXT(LNPOSN+1,-1);
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goto L395;
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L340: SHFTXT(LNPOSN+2,-2);
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STATE=0;
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CASE=2;
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L345: if(PARMS[NPARMS] < 0) goto L395;
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{long x = NPARMS+1; if(PARMS[x] < 0)CASE=0;}
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PUTTXT(PARMS[NPARMS],STATE,CASE,0);
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NPARMS=NPARMS+1;
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goto L345;
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L360: PRMTYP=PARMS[NPARMS];
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SHFTXT(LNPOSN+2,PRMTYP-2);
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if(PRMTYP == 0) goto L395;
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/* 365 */ for (I=1; I<=PRMTYP; I++) {
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INLINE[LNPOSN]=0;
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L365: LNPOSN=LNPOSN+1;
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} /* end loop */
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goto L395;
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L380: SHFTXT(LNPOSN+2,-2);
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STATE=0;
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CASE= -1;
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if(PRMTYP == 31)CASE=1;
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if(PRMTYP == 33)CASE=0;
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I=LNPOSN;
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PUTTXT(PARMS[NPARMS],STATE,CASE,0);
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{long x = NPARMS+1; PUTTXT(PARMS[x],STATE,CASE,0);}
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if(PRMTYP == 13 && INLINE[I] >= 37 && INLINE[I] <=
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62)INLINE[I]=INLINE[I]-26;
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NPARMS=NPARMS+2;
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goto L32;
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L40: if(BLANK)TYPE0();
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BLANK=false;
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TYPE();
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K=L+1;
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if(LINES[K] >= 0) goto L10;
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return;
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}
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#define SPEAK(N) fSPEAK(N)
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#undef PSPEAK
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void fPSPEAK(long MSG,long SKIP) {
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long I, M;
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/* FIND THE SKIP+1ST MESSAGE FROM MSG AND PRINT IT. MSG SHOULD BE THE INDEX OF
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* THE INVENTORY MESSAGE FOR OBJECT. (INVEN+N+1 MESSAGE IS PROP=N MESSAGE). */
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M=PTEXT[MSG];
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if(SKIP < 0) goto L9;
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/* 3 */ for (I=0; I<=SKIP; I++) {
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L1: M=IABS(LINES[M]);
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if(LINES[M] >= 0) goto L1;
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L3: /*etc*/ ;
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} /* end loop */
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L9: SPEAK(M);
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return;
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}
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#define PSPEAK(MSG,SKIP) fPSPEAK(MSG,SKIP)
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#undef RSPEAK
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void fRSPEAK(long I) {
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;
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/* PRINT THE I-TH "RANDOM" MESSAGE (SECTION 6 OF DATABASE). */
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if(I != 0)SPEAK(RTEXT[I]);
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return;
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}
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#define RSPEAK(I) fRSPEAK(I)
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#undef SETPRM
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void fSETPRM(long FIRST, long P1, long P2) {
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;
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/* STORES PARAMETERS INTO THE PRMCOM PARMS ARRAY FOR USE BY SPEAK. P1 AND P2
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* ARE STORED INTO PARMS(FIRST) AND PARMS(FIRST+1). */
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if(FIRST >= 25)BUG(29);
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PARMS[FIRST]=P1;
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{long x = FIRST+1; PARMS[x]=P2;}
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return;
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}
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#define SETPRM(FIRST,P1,P2) fSETPRM(FIRST,P1,P2)
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#undef GETIN
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#define WORD1 (*wORD1)
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#define WORD1X (*wORD1X)
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#define WORD2 (*wORD2)
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#define WORD2X (*wORD2X)
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void fGETIN(long *wORD1, long *wORD1X, long *wORD2, long *wORD2X) {
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long JUNK;
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/* GET A COMMAND FROM THE ADVENTURER. SNARF OUT THE FIRST WORD, PAD IT WITH
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* BLANKS, AND RETURN IT IN WORD1. CHARS 6 THRU 10 ARE RETURNED IN WORD1X, IN
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* CASE WE NEED TO PRINT OUT THE WHOLE WORD IN AN ERROR MESSAGE. ANY NUMBER OF
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* BLANKS MAY FOLLOW THE WORD. IF A SECOND WORD APPEARS, IT IS RETURNED IN
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* WORD2 (CHARS 6 THRU 10 IN WORD2X), ELSE WORD2 IS -1. */
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L10: if(BLKLIN)TYPE0();
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MAPLIN(false);
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WORD1=GETTXT(true,true,true,0);
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if(BLKLIN && WORD1 < 0) goto L10;
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WORD1X=GETTXT(false,true,true,0);
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L12: JUNK=GETTXT(false,true,true,0);
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if(JUNK > 0) goto L12;
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WORD2=GETTXT(true,true,true,0);
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WORD2X=GETTXT(false,true,true,0);
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L22: JUNK=GETTXT(false,true,true,0);
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if(JUNK > 0) goto L22;
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if(GETTXT(true,true,true,0) <= 0)return;
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RSPEAK(53);
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goto L10;
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}
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#undef WORD1
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#undef WORD1X
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#undef WORD2
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#undef WORD2X
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#define GETIN(WORD1,WORD1X,WORD2,WORD2X) fGETIN(&WORD1,&WORD1X,&WORD2,&WORD2X)
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#undef YES
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long fYES(long X, long Y, long Z) {
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long YES, REPLY, JUNK1, JUNK2, JUNK3;
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/* PRINT MESSAGE X, WAIT FOR YES/NO ANSWER. IF YES, PRINT Y AND RETURN TRUE;
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* IF NO, PRINT Z AND RETURN FALSE. */
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L1: RSPEAK(X);
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GETIN(REPLY,JUNK1,JUNK2,JUNK3);
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if(REPLY == MAKEWD(250519) || REPLY == MAKEWD(25)) goto L10;
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if(REPLY == MAKEWD(1415) || REPLY == MAKEWD(14)) goto L20;
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RSPEAK(185);
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goto L1;
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L10: YES=true;
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RSPEAK(Y);
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return(YES);
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L20: YES=false;
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RSPEAK(Z);
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return(YES);
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}
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/* LINE-PARSING ROUTINES (GETNUM, GETTXT, MAKEWD, PUTTXT, SHFTXT, TYPE0)
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*/
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/* THE ROUTINES ON THIS PAGE HANDLE ALL THE STUFF THAT WOULD NORMALLY BE
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* TAKEN CARE OF BY FORMAT STATEMENTS. WE DO IT THIS WAY INSTEAD SO THAT
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* WE CAN HANDLE TEXTUAL DATA IN A MACHINE INDEPENDENT FASHION. ALL THE
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* MACHINE DEPENDENT I/O STUFF IS ON THE FOLLOWING PAGE. SEE THAT PAGE
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* FOR A DESCRIPTION OF MAPCOM'S INLINE ARRAY. */
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#define YES(X,Y,Z) fYES(X,Y,Z)
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#undef GETNUM
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long fGETNUM(long K) {
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long DIGIT, GETNUM, SIGN;
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/* OBTAIN THE NEXT INTEGER FROM AN INPUT LINE. IF K>0, WE FIRST READ A
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* NEW INPUT LINE FROM A FILE; IF K<0, WE READ A LINE FROM THE KEYBOARD;
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* IF K=0 WE USE A LINE THAT HAS ALREADY BEEN READ (AND PERHAPS PARTIALLY
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* SCANNED). IF WE'RE AT THE END OF THE LINE OR ENCOUNTER AN ILLEGAL
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* CHARACTER (NOT A DIGIT, HYPHEN, OR BLANK), WE RETURN 0. */
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if(K != 0)MAPLIN(K > 0);
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GETNUM=0;
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L10: if(LNPOSN > LNLENG)return(GETNUM);
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if(INLINE[LNPOSN] != 0) goto L20;
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LNPOSN=LNPOSN+1;
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goto L10;
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L20: SIGN=1;
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if(INLINE[LNPOSN] != 9) goto L32;
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SIGN= -1;
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L30: LNPOSN=LNPOSN+1;
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L32: if(LNPOSN > LNLENG || INLINE[LNPOSN] == 0) goto L42;
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DIGIT=INLINE[LNPOSN]-64;
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if(DIGIT < 0 || DIGIT > 9) goto L40;
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GETNUM=GETNUM*10+DIGIT;
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goto L30;
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L40: GETNUM=0;
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L42: GETNUM=GETNUM*SIGN;
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LNPOSN=LNPOSN+1;
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return(GETNUM);
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}
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#define GETNUM(K) fGETNUM(K)
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#undef GETTXT
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long fGETTXT(long SKIP,long ONEWRD, long UPPER, long HASH) {
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long CHAR, GETTXT, I; static long SPLITTING = -1;
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/* TAKE CHARACTERS FROM AN INPUT LINE AND PACK THEM INTO 30-BIT WORDS.
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* SKIP SAYS TO SKIP LEADING BLANKS. ONEWRD SAYS STOP IF WE COME TO A
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* BLANK. UPPER SAYS TO MAP ALL LETTERS TO UPPERCASE. HASH MAY BE USED
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* AS A PARAMETER FOR ENCRYPTING THE TEXT IF DESIRED; HOWEVER, A HASH OF 0
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* SHOULD RESULT IN UNMODIFIED BYTES BEING PACKED. IF WE REACH THE
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* END OF THE LINE, THE WORD IS FILLED UP WITH BLANKS (WHICH ENCODE AS 0'S).
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* IF WE'RE ALREADY AT END OF LINE WHEN GETTXT IS CALLED, WE RETURN -1. */
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if(LNPOSN != SPLITTING)SPLITTING = -1;
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GETTXT= -1;
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L10: if(LNPOSN > LNLENG)return(GETTXT);
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if((!SKIP) || INLINE[LNPOSN] != 0) goto L11;
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LNPOSN=LNPOSN+1;
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goto L10;
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L11: GETTXT=0;
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/* 15 */ for (I=1; I<=5; I++) {
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GETTXT=GETTXT*64;
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if(LNPOSN > LNLENG || (ONEWRD && INLINE[LNPOSN] == 0)) goto L15;
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CHAR=INLINE[LNPOSN];
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if(CHAR >= 63) goto L12;
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SPLITTING = -1;
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if(UPPER && CHAR >= 37)CHAR=CHAR-26;
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GETTXT=GETTXT+CHAR;
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goto L14;
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L12: if(SPLITTING == LNPOSN) goto L13;
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GETTXT=GETTXT+63;
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SPLITTING = LNPOSN;
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goto L15;
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L13: GETTXT=GETTXT+CHAR-63;
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SPLITTING = -1;
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L14: LNPOSN=LNPOSN+1;
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L15: /*etc*/ ;
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} /* end loop */
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if(HASH)GETTXT=GETTXT+MOD(HASH*13579L+5432L,97531L)*12345L+HASH;
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return(GETTXT);
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}
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#define GETTXT(SKIP,ONEWRD,UPPER,HASH) fGETTXT(SKIP,ONEWRD,UPPER,HASH)
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#undef MAKEWD
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long fMAKEWD(long LETTRS) {
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long I, L, MAKEWD;
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/* COMBINE FIVE UPPERCASE LETTERS (REPRESENTED BY PAIRS OF DECIMAL DIGITS
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* IN LETTRS) TO FORM A 30-BIT VALUE MATCHING THE ONE THAT GETTXT WOULD
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* RETURN GIVEN THOSE CHARACTERS PLUS TRAILING BLANKS AND HASH=0. CAUTION:
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* LETTRS WILL OVERFLOW 31 BITS IF 5-LETTER WORD STARTS WITH V-Z. AS A
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* KLUDGEY WORKAROUND, YOU CAN INCREMENT A LETTER BY 5 BY ADDING 50 TO
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* THE NEXT PAIR OF DIGITS. */
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MAKEWD=0;
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I=1;
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L=LETTRS;
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L10: MAKEWD=MAKEWD+I*(MOD(L,50)+10);
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I=I*64;
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if(MOD(L,100) > 50)MAKEWD=MAKEWD+I*5;
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L=L/100;
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if(L != 0) goto L10;
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I=64L*64L*64L*64L*64L/I;
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MAKEWD=MAKEWD*I;
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return(MAKEWD);
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}
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#define MAKEWD(LETTRS) fMAKEWD(LETTRS)
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#undef PUTTXT
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#define STATE (*sTATE)
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void fPUTTXT(long WORD, long *sTATE, long CASE, long HASH) {
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long ALPH1, ALPH2, BYTE, DIV, I, W;
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/* UNPACK THE 30-BIT VALUE IN WORD TO OBTAIN UP TO 5 INTEGER-ENCODED CHARS,
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* AND STORE THEM IN INLINE STARTING AT LNPOSN. IF LNLENG>=LNPOSN, SHIFT
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* EXISTING CHARACTERS TO THE RIGHT TO MAKE ROOM. HASH MUST BE THE SAME
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* AS IT WAS WHEN GETTXT CREATED THE 30-BIT WORD. STATE WILL BE ZERO WHEN
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* PUTTXT IS CALLED WITH THE FIRST OF A SEQUENCE OF WORDS, BUT IS THEREAFTER
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* UNCHANGED BY THE CALLER, SO PUTTXT CAN USE IT TO MAINTAIN STATE ACROSS
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* CALLS. LNPOSN AND LNLENG ARE INCREMENTED BY THE NUMBER OF CHARS STORED.
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* IF CASE=1, ALL LETTERS ARE MADE UPPERCASE; IF -1, LOWERCASE; IF 0, AS IS.
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* ANY OTHER VALUE FOR CASE IS THE SAME AS 0 BUT ALSO CAUSES TRAILING BLANKS
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* TO BE INCLUDED (IN ANTICIPATION OF SUBSEQUENT ADDITIONAL TEXT). */
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ALPH1=13*CASE+24;
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ALPH2=26*IABS(CASE)+ALPH1;
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if(IABS(CASE) > 1)ALPH1=ALPH2;
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/* ALPH1&2 DEFINE RANGE OF WRONG-CASE CHARS, 11-36 OR 37-62 OR EMPTY. */
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DIV=64L*64L*64L*64L;
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W=WORD;
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if(HASH)W=W-MOD(HASH*13579L+5432L,97531L)*12345L-HASH;
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/* 18 */ for (I=1; I<=5; I++) {
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if(W <= 0 && STATE == 0 && IABS(CASE) <= 1)return;
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BYTE=W/DIV;
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if(STATE != 0 || BYTE != 63) goto L12;
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STATE=63;
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goto L18;
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L12: SHFTXT(LNPOSN,1);
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STATE=STATE+BYTE;
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if(STATE < ALPH2 && STATE >= ALPH1)STATE=STATE-26*CASE;
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INLINE[LNPOSN]=STATE;
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LNPOSN=LNPOSN+1;
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STATE=0;
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L18: W=(W-BYTE*DIV)*64;
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} /* end loop */
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return;
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}
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#undef STATE
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#define PUTTXT(WORD,STATE,CASE,HASH) fPUTTXT(WORD,&STATE,CASE,HASH)
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#undef SHFTXT
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void fSHFTXT(long FROM, long DELTA) {
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long I, II, JJ;
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/* MOVE INLINE(N) TO INLINE(N+DELTA) FOR N=FROM,LNLENG. DELTA CAN BE
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* NEGATIVE. LNLENG IS UPDATED; LNPOSN IS NOT CHANGED. */
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if(LNLENG < FROM || DELTA == 0) goto L2;
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/* 1 */ for (I=FROM; I<=LNLENG; I++) {
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II=I;
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if(DELTA > 0)II=FROM+LNLENG-I;
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JJ=II+DELTA;
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L1: INLINE[JJ]=INLINE[II];
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} /* end loop */
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L2: LNLENG=LNLENG+DELTA;
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return;
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}
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#define SHFTXT(FROM,DELTA) fSHFTXT(FROM,DELTA)
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#undef TYPE0
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void fTYPE0() {
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long TEMP;
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/* TYPE A BLANK LINE. THIS PROCEDURE IS PROVIDED AS A CONVENIENCE FOR CALLERS
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* WHO OTHERWISE HAVE NO USE FOR MAPCOM. */
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TEMP=LNLENG;
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LNLENG=0;
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TYPE();
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LNLENG=TEMP;
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return;
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}
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#define TYPE0() fTYPE0()
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/* SUSPEND/RESUME I/O ROUTINES (SAVWDS, SAVARR, SAVWRD) */
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#undef SAVWDS
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void fSAVWDS(long *W1, long *W2, long *W3, long *W4, long *W5, long *W6, long *W7) {
|
|
|
|
/* WRITE OR READ 7 VARIABLES. SEE SAVWRD. */
|
|
|
|
|
|
SAVWRD(0,(*W1));
|
|
SAVWRD(0,(*W2));
|
|
SAVWRD(0,(*W3));
|
|
SAVWRD(0,(*W4));
|
|
SAVWRD(0,(*W5));
|
|
SAVWRD(0,(*W6));
|
|
SAVWRD(0,(*W7));
|
|
return;
|
|
}
|
|
|
|
|
|
#define SAVWDS(W1,W2,W3,W4,W5,W6,W7) fSAVWDS(&W1,&W2,&W3,&W4,&W5,&W6,&W7)
|
|
#undef SAVARR
|
|
void fSAVARR(long ARR[], long N) {
|
|
long I;
|
|
|
|
/* WRITE OR READ AN ARRAY OF N WORDS. SEE SAVWRD. */
|
|
|
|
|
|
/* 1 */ for (I=1; I<=N; I++) {
|
|
L1: SAVWRD(0,ARR[I]);
|
|
} /* end loop */
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define SAVARR(ARR,N) fSAVARR(ARR,N)
|
|
#undef SAVWRD
|
|
#define WORD (*wORD)
|
|
void fSAVWRD(long OP, long *wORD) {
|
|
static long BUF[250], CKSUM = 0, H1, HASH = 0, N = 0, STATE = 0;
|
|
|
|
/* IF OP<0, START WRITING A FILE, USING WORD TO INITIALISE ENCRYPTION; SAVE
|
|
* WORD IN THE FILE. IF OP>0, START READING A FILE; READ THE FILE TO FIND
|
|
* THE VALUE WITH WHICH TO DECRYPT THE REST. IN EITHER CASE, IF A FILE IS
|
|
* ALREADY OPEN, FINISH WRITING/READING IT AND DON'T START A NEW ONE. IF OP=0,
|
|
* READ/WRITE A SINGLE WORD. WORDS ARE BUFFERED IN CASE THAT MAKES FOR MORE
|
|
* EFFICIENT DISK USE. WE ALSO COMPUTE A SIMPLE CHECKSUM TO CATCH ELEMENTARY
|
|
* POKING WITHIN THE SAVED FILE. WHEN WE FINISH READING/WRITING THE FILE,
|
|
* WE STORE ZERO INTO WORD IF THERE'S NO CHECKSUM ERROR, ELSE NONZERO. */
|
|
|
|
|
|
if(OP != 0){long ifvar; ifvar=(STATE); switch (ifvar<0? -1 : ifvar>0? 1 :
|
|
0) { case -1: goto L30; case 0: goto L10; case 1: goto L30; }}
|
|
if(STATE == 0)return;
|
|
if(N == 250)SAVEIO(1,STATE > 0,BUF);
|
|
N=MOD(N,250)+1;
|
|
H1=MOD(HASH*1093L+221573L,1048576L);
|
|
HASH=MOD(H1*1093L+221573L,1048576L);
|
|
H1=MOD(H1,1234)*765432+MOD(HASH,123);
|
|
N--;
|
|
if(STATE > 0)WORD=BUF[N]+H1;
|
|
BUF[N]=WORD-H1;
|
|
N++;
|
|
CKSUM=MOD(CKSUM*13+WORD,1000000000L);
|
|
return;
|
|
|
|
L10: STATE=OP;
|
|
SAVEIO(0,STATE > 0,BUF);
|
|
N=1;
|
|
if(STATE > 0) goto L15;
|
|
HASH=MOD(WORD,1048576L);
|
|
BUF[0]=1234L*5678L-HASH;
|
|
L13: CKSUM=BUF[0];
|
|
return;
|
|
|
|
L15: SAVEIO(1,true,BUF);
|
|
HASH=MOD(1234L*5678L-BUF[0],1048576L);
|
|
goto L13;
|
|
|
|
L30: if(N == 250)SAVEIO(1,STATE > 0,BUF);
|
|
N=MOD(N,250)+1;
|
|
if(STATE > 0) goto L32;
|
|
N--; BUF[N]=CKSUM; N++;
|
|
SAVEIO(1,false,BUF);
|
|
L32: N--; WORD=BUF[N]-CKSUM; N++;
|
|
SAVEIO(-1,STATE > 0,BUF);
|
|
STATE=0;
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
/* DATA STRUC. ROUTINES (VOCAB, DSTROY, JUGGLE, MOVE, PUT, CARRY, DROP, ATDWRF)
|
|
*/
|
|
|
|
#undef WORD
|
|
#define SAVWRD(OP,WORD) fSAVWRD(OP,&WORD)
|
|
#undef VOCAB
|
|
long fVOCAB(long ID, long INIT) {
|
|
long HASH, I, VOCAB;
|
|
|
|
/* LOOK UP ID IN THE VOCABULARY (ATAB) AND RETURN ITS "DEFINITION" (KTAB), OR
|
|
* -1 IF NOT FOUND. IF INIT IS POSITIVE, THIS IS AN INITIALISATION CALL SETTING
|
|
* UP A KEYWORD VARIABLE, AND NOT FINDING IT CONSTITUTES A BUG. IT ALSO MEANS
|
|
* THAT ONLY KTAB VALUES WHICH TAKEN OVER 1000 EQUAL INIT MAY BE CONSIDERED.
|
|
* (THUS "STEPS", WHICH IS A MOTION VERB AS WELL AS AN OBJECT, MAY BE LOCATED
|
|
* AS AN OBJECT.) AND IT ALSO MEANS THE KTAB VALUE IS TAKEN MOD 1000. */
|
|
|
|
HASH=10000;
|
|
/* 1 */ for (I=1; I<=TABSIZ; I++) {
|
|
if(KTAB[I] == -1) goto L2;
|
|
HASH=HASH+7;
|
|
if(INIT >= 0 && KTAB[I]/1000 != INIT) goto L1;
|
|
if(ATAB[I] == ID+HASH*HASH) goto L3;
|
|
L1: /*etc*/ ;
|
|
} /* end loop */
|
|
BUG(21);
|
|
|
|
L2: VOCAB= -1;
|
|
if(INIT < 0)return(VOCAB);
|
|
BUG(5);
|
|
|
|
L3: VOCAB=KTAB[I];
|
|
if(INIT >= 0)VOCAB=MOD(VOCAB,1000);
|
|
return(VOCAB);
|
|
}
|
|
|
|
|
|
|
|
#define VOCAB(ID,INIT) fVOCAB(ID,INIT)
|
|
#undef DSTROY
|
|
void fDSTROY(long OBJECT) {
|
|
;
|
|
|
|
/* PERMANENTLY ELIMINATE "OBJECT" BY MOVING TO A NON-EXISTENT LOCATION. */
|
|
|
|
|
|
MOVE(OBJECT,0);
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define DSTROY(OBJECT) fDSTROY(OBJECT)
|
|
#undef JUGGLE
|
|
void fJUGGLE(OBJECT)long OBJECT; {
|
|
long I, J;
|
|
|
|
/* JUGGLE AN OBJECT BY PICKING IT UP AND PUTTING IT DOWN AGAIN, THE PURPOSE
|
|
* BEING TO GET THE OBJECT TO THE FRONT OF THE CHAIN OF THINGS AT ITS LOC. */
|
|
|
|
|
|
I=PLACE[OBJECT];
|
|
J=FIXED[OBJECT];
|
|
MOVE(OBJECT,I);
|
|
MOVE(OBJECT+100,J);
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define JUGGLE(OBJECT) fJUGGLE(OBJECT)
|
|
#undef MOVE
|
|
void fMOVE(OBJECT,WHERE)long OBJECT, WHERE; {
|
|
long FROM;
|
|
|
|
/* PLACE ANY OBJECT ANYWHERE BY PICKING IT UP AND DROPPING IT. MAY ALREADY BE
|
|
* TOTING, IN WHICH CASE THE CARRY IS A NO-OP. MUSTN'T PICK UP OBJECTS WHICH
|
|
* ARE NOT AT ANY LOC, SINCE CARRY WANTS TO REMOVE OBJECTS FROM ATLOC CHAINS. */
|
|
|
|
|
|
if(OBJECT > 100) goto L1;
|
|
FROM=PLACE[OBJECT];
|
|
goto L2;
|
|
L1: {long x = OBJECT-100; FROM=FIXED[x];}
|
|
L2: if(FROM > 0 && FROM <= 300)CARRY(OBJECT,FROM);
|
|
DROP(OBJECT,WHERE);
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define MOVE(OBJECT,WHERE) fMOVE(OBJECT,WHERE)
|
|
#undef PUT
|
|
long fPUT(OBJECT,WHERE,PVAL)long OBJECT, PVAL, WHERE; {
|
|
long PUT;
|
|
|
|
/* PUT IS THE SAME AS MOVE, EXCEPT IT RETURNS A VALUE USED TO SET UP THE
|
|
* NEGATED PROP VALUES FOR THE REPOSITORY OBJECTS. */
|
|
|
|
|
|
MOVE(OBJECT,WHERE);
|
|
PUT=(-1)-PVAL;
|
|
return(PUT);
|
|
}
|
|
|
|
|
|
|
|
#define PUT(OBJECT,WHERE,PVAL) fPUT(OBJECT,WHERE,PVAL)
|
|
#undef CARRY
|
|
void fCARRY(OBJECT,WHERE)long OBJECT, WHERE; {
|
|
long TEMP;
|
|
|
|
/* START TOTING AN OBJECT, REMOVING IT FROM THE LIST OF THINGS AT ITS FORMER
|
|
* LOCATION. INCR HOLDNG UNLESS IT WAS ALREADY BEING TOTED. IF OBJECT>100
|
|
* (MOVING "FIXED" SECOND LOC), DON'T CHANGE PLACE OR HOLDNG. */
|
|
|
|
|
|
if(OBJECT > 100) goto L5;
|
|
if(PLACE[OBJECT] == -1)return;
|
|
PLACE[OBJECT]= -1;
|
|
HOLDNG=HOLDNG+1;
|
|
L5: if(ATLOC[WHERE] != OBJECT) goto L6;
|
|
ATLOC[WHERE]=LINK[OBJECT];
|
|
return;
|
|
L6: TEMP=ATLOC[WHERE];
|
|
L7: if(LINK[TEMP] == OBJECT) goto L8;
|
|
TEMP=LINK[TEMP];
|
|
goto L7;
|
|
L8: LINK[TEMP]=LINK[OBJECT];
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define CARRY(OBJECT,WHERE) fCARRY(OBJECT,WHERE)
|
|
#undef DROP
|
|
void fDROP(OBJECT,WHERE)long OBJECT, WHERE; {
|
|
;
|
|
|
|
/* PLACE AN OBJECT AT A GIVEN LOC, PREFIXING IT ONTO THE ATLOC LIST. DECR
|
|
* HOLDNG IF THE OBJECT WAS BEING TOTED. */
|
|
|
|
|
|
if(OBJECT > 100) goto L1;
|
|
if(PLACE[OBJECT] == -1)HOLDNG=HOLDNG-1;
|
|
PLACE[OBJECT]=WHERE;
|
|
goto L2;
|
|
L1: {long x = OBJECT-100; FIXED[x]=WHERE;}
|
|
L2: if(WHERE <= 0)return;
|
|
LINK[OBJECT]=ATLOC[WHERE];
|
|
ATLOC[WHERE]=OBJECT;
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define DROP(OBJECT,WHERE) fDROP(OBJECT,WHERE)
|
|
#undef ATDWRF
|
|
long fATDWRF(WHERE)long WHERE; {
|
|
long ATDWRF, I;
|
|
|
|
/* RETURN THE INDEX OF FIRST DWARF AT THE GIVEN LOCATION, ZERO IF NO DWARF IS
|
|
* THERE (OR IF DWARVES NOT ACTIVE YET), -1 IF ALL DWARVES ARE DEAD. IGNORE
|
|
* THE PIRATE (6TH DWARF). */
|
|
|
|
|
|
ATDWRF=0;
|
|
if(DFLAG < 2)return(ATDWRF);
|
|
ATDWRF= -1;
|
|
/* 1 */ for (I=1; I<=5; I++) {
|
|
if(DLOC[I] == WHERE) goto L2;
|
|
L1: if(DLOC[I] != 0)ATDWRF=0;
|
|
} /* end loop */
|
|
return(ATDWRF);
|
|
|
|
L2: ATDWRF=I;
|
|
return(ATDWRF);
|
|
}
|
|
|
|
|
|
|
|
|
|
#define ATDWRF(WHERE) fATDWRF(WHERE)
|
|
|
|
|
|
|
|
/* UTILITY ROUTINES (SETBIT, TSTBIT, RAN, RNDVOC, BUG) */
|
|
|
|
#undef SETBIT
|
|
long fSETBIT(BIT)long BIT; {
|
|
long I, SETBIT;
|
|
|
|
/* RETURNS 2**BIT FOR USE IN CONSTRUCTING BIT-MASKS. */
|
|
|
|
|
|
SETBIT=1;
|
|
if(BIT <= 0)return(SETBIT);
|
|
/* 1 */ for (I=1; I<=BIT; I++) {
|
|
L1: SETBIT=SETBIT+SETBIT;
|
|
} /* end loop */
|
|
return(SETBIT);
|
|
}
|
|
|
|
|
|
|
|
#define SETBIT(BIT) fSETBIT(BIT)
|
|
#undef TSTBIT
|
|
long fTSTBIT(MASK,BIT)long BIT, MASK; {
|
|
long TSTBIT;
|
|
|
|
/* RETURNS TRUE IF THE SPECIFIED BIT IS SET IN THE MASK. */
|
|
|
|
|
|
TSTBIT=MOD(MASK/SETBIT(BIT),2) != 0;
|
|
return(TSTBIT);
|
|
}
|
|
|
|
|
|
|
|
#define TSTBIT(MASK,BIT) fTSTBIT(MASK,BIT)
|
|
#undef RAN
|
|
long fRAN(RANGE)long RANGE; {
|
|
static long D, R = 0, RAN, T;
|
|
|
|
/* SINCE THE RAN FUNCTION IN LIB40 SEEMS TO BE A REAL LOSE, WE'LL USE ONE OF
|
|
* OUR OWN. IT'S BEEN RUN THROUGH MANY OF THE TESTS IN KNUTH VOL. 2 AND
|
|
* SEEMS TO BE QUITE RELIABLE. RAN RETURNS A VALUE UNIFORMLY SELECTED
|
|
* BETWEEN 0 AND RANGE-1. */
|
|
|
|
|
|
D=1;
|
|
if(R != 0 && RANGE >= 0) goto L1;
|
|
DATIME(D,T);
|
|
R=MOD(T+5,1048576L);
|
|
D=1000+MOD(D,1000);
|
|
L1: /* 2 */ for (T=1; T<=D; T++) {
|
|
L2: R=MOD(R*1093L+221587L,1048576L);
|
|
} /* end loop */
|
|
RAN=(RANGE*R)/1048576;
|
|
return(RAN);
|
|
}
|
|
|
|
|
|
|
|
#define RAN(RANGE) fRAN(RANGE)
|
|
#undef RNDVOC
|
|
long fRNDVOC(CHAR,FORCE)long CHAR, FORCE; {
|
|
long DIV, I, J, RNDVOC;
|
|
|
|
/* SEARCHES THE VOCABULARY FOR A WORD WHOSE SECOND CHARACTER IS CHAR, AND
|
|
* CHANGES THAT WORD SUCH THAT EACH OF THE OTHER FOUR CHARACTERS IS A
|
|
* RANDOM LETTER. IF FORCE IS NON-ZERO, IT IS USED AS THE NEW WORD.
|
|
* RETURNS THE NEW WORD. */
|
|
|
|
|
|
RNDVOC=FORCE;
|
|
if(RNDVOC != 0) goto L3;
|
|
/* 1 */ for (I=1; I<=5; I++) {
|
|
J=11+RAN(26);
|
|
if(I == 2)J=CHAR;
|
|
L1: RNDVOC=RNDVOC*64+J;
|
|
} /* end loop */
|
|
L3: J=10000;
|
|
DIV=64L*64L*64L;
|
|
/* 5 */ for (I=1; I<=TABSIZ; I++) {
|
|
J=J+7;
|
|
if(MOD((ATAB[I]-J*J)/DIV,64L) == CHAR) goto L8;
|
|
L5: /*etc*/ ;
|
|
} /* end loop */
|
|
BUG(5);
|
|
|
|
L8: ATAB[I]=RNDVOC+J*J;
|
|
return(RNDVOC);
|
|
}
|
|
|
|
|
|
|
|
#define RNDVOC(CHAR,FORCE) fRNDVOC(CHAR,FORCE)
|
|
#undef BUG
|
|
void fBUG(NUM)long NUM; {
|
|
|
|
/* THE FOLLOWING CONDITIONS ARE CURRENTLY CONSIDERED FATAL BUGS. NUMBERS < 20
|
|
* ARE DETECTED WHILE READING THE DATABASE; THE OTHERS OCCUR AT "RUN TIME".
|
|
* 0 MESSAGE LINE > 70 CHARACTERS
|
|
* 1 NULL LINE IN MESSAGE
|
|
* 2 TOO MANY WORDS OF MESSAGES
|
|
* 3 TOO MANY TRAVEL OPTIONS
|
|
* 4 TOO MANY VOCABULARY WORDS
|
|
* 5 REQUIRED VOCABULARY WORD NOT FOUND
|
|
* 6 TOO MANY RTEXT MESSAGES
|
|
* 7 TOO MANY HINTS
|
|
* 8 LOCATION HAS COND BIT BEING SET TWICE
|
|
* 9 INVALID SECTION NUMBER IN DATABASE
|
|
* 10 TOO MANY LOCATIONS
|
|
* 11 TOO MANY CLASS OR TURN MESSAGES
|
|
* 20 SPECIAL TRAVEL (500>L>300) EXCEEDS GOTO LIST
|
|
* 21 RAN OFF END OF VOCABULARY TABLE
|
|
* 22 VOCABULARY TYPE (N/1000) NOT BETWEEN 0 AND 3
|
|
* 23 INTRANSITIVE ACTION VERB EXCEEDS GOTO LIST
|
|
* 24 TRANSITIVE ACTION VERB EXCEEDS GOTO LIST
|
|
* 25 CONDITIONAL TRAVEL ENTRY WITH NO ALTERNATIVE
|
|
* 26 LOCATION HAS NO TRAVEL ENTRIES
|
|
* 27 HINT NUMBER EXCEEDS GOTO LIST
|
|
* 28 INVALID MONTH RETURNED BY DATE FUNCTION
|
|
* 29 TOO MANY PARAMETERS GIVEN TO SETPRM */
|
|
|
|
printf("Fatal error %ld. See source code for interpretation.\n",
|
|
NUM);
|
|
exit(0);
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
/* MACHINE DEPENDENT ROUTINES (MAPLIN, TYPE, MPINIT, SAVEIO) */
|
|
|
|
#define BUG(NUM) fBUG(NUM)
|
|
#undef MAPLIN
|
|
void fMAPLIN(FIL)long FIL; {
|
|
long I, VAL; static FILE *OPENED = NULL;
|
|
|
|
/* READ A LINE OF INPUT, EITHER FROM A FILE (IF FIL=.TRUE.) OR FROM THE
|
|
* KEYBOARD, TRANSLATE THE CHARS TO INTEGERS IN THE RANGE 0-126 AND STORE
|
|
* THEM IN THE COMMON ARRAY "INLINE". INTEGER VALUES ARE AS FOLLOWS:
|
|
* 0 = SPACE [ASCII CODE 40 OCTAL, 32 DECIMAL]
|
|
* 1-2 = !" [ASCII 41-42 OCTAL, 33-34 DECIMAL]
|
|
* 3-10 = '()*+,-. [ASCII 47-56 OCTAL, 39-46 DECIMAL]
|
|
* 11-36 = UPPER-CASE LETTERS
|
|
* 37-62 = LOWER-CASE LETTERS
|
|
* 63 = PERCENT (%) [ASCII 45 OCTAL, 37 DECIMAL]
|
|
* 64-73 = DIGITS, 0 THROUGH 9
|
|
* REMAINING CHARACTERS CAN BE TRANSLATED ANY WAY THAT IS CONVENIENT;
|
|
* THE "TYPE" ROUTINE BELOW IS USED TO MAP THEM BACK TO CHARACTERS WHEN
|
|
* NECESSARY. THE ABOVE MAPPINGS ARE REQUIRED SO THAT CERTAIN SPECIAL
|
|
* CHARACTERS ARE KNOWN TO FIT IN 6 BITS AND/OR CAN BE EASILY SPOTTED.
|
|
* ARRAY ELEMENTS BEYOND THE END OF THE LINE SHOULD BE FILLED WITH 0,
|
|
* AND LNLENG SHOULD BE SET TO THE INDEX OF THE LAST CHARACTER.
|
|
*
|
|
* IF THE DATA FILE USES A CHARACTER OTHER THAN SPACE (E.G., TAB) TO
|
|
* SEPARATE NUMBERS, THAT CHARACTER SHOULD ALSO TRANSLATE TO 0.
|
|
*
|
|
* THIS PROCEDURE MAY USE THE MAP1,MAP2 ARRAYS TO MAINTAIN STATIC DATA FOR
|
|
* THE MAPPING. MAP2(1) IS SET TO 0 WHEN THE PROGRAM STARTS
|
|
* AND IS NOT CHANGED THEREAFTER UNLESS THE ROUTINES ON THIS PAGE CHOOSE
|
|
* TO DO SO.
|
|
*
|
|
* NOTE THAT MAPLIN IS EXPECTED TO OPEN THE FILE THE FIRST TIME IT IS
|
|
* ASKED TO READ A LINE FROM IT. THAT IS, THERE IS NO OTHER PLACE WHERE
|
|
* THE DATA FILE IS OPENED. */
|
|
|
|
|
|
if(MAP2[1] == 0)MPINIT();
|
|
|
|
if(FIL) goto L15;
|
|
IGNORE(fgets(INLINE+1, sizeof(INLINE)-1, stdin));
|
|
if(feof(stdin)) score(1);
|
|
goto L20;
|
|
|
|
L15: if(!OPENED){
|
|
OPENED=fopen("adventure.text","r" /* NOT binary */);
|
|
if(!OPENED){printf("Can't read adventure.text!\n"); exit(0);}
|
|
}
|
|
IGNORE(fgets(INLINE+1,100,OPENED));
|
|
|
|
L20: LNLENG=0;
|
|
/* 25 */ for (I=1; I<=100 && INLINE[I]!=0; I++) {
|
|
VAL=INLINE[I]+1;
|
|
INLINE[I]=MAP1[VAL];
|
|
L25: if(INLINE[I] != 0)LNLENG=I;
|
|
} /* end loop */
|
|
LNPOSN=1;
|
|
if(FIL && LNLENG == 0) goto L15;
|
|
/* ABOVE IS TO GET AROUND AN F40 COMPILER BUG WHEREIN IT READS A BLANK
|
|
* LINE WHENEVER A CRLF IS BROKEN ACROSS A RECORD BOUNDARY. */
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define MAPLIN(FIL) fMAPLIN(FIL)
|
|
#undef TYPE
|
|
void fTYPE() {
|
|
long I, VAL;
|
|
|
|
/* TYPE THE FIRST "LNLENG" CHARACTERS STORED IN INLINE, MAPPING THEM
|
|
* FROM INTEGERS TO TEXT PER THE RULES DESCRIBED ABOVE. INLINE(I),
|
|
* I=1,LNLENG MAY BE CHANGED BY THIS ROUTINE. */
|
|
|
|
|
|
if(LNLENG != 0) goto L10;
|
|
printf("\n");
|
|
return;
|
|
|
|
L10: if(MAP2[1] == 0)MPINIT();
|
|
/* 20 */ for (I=1; I<=LNLENG; I++) {
|
|
VAL=INLINE[I];
|
|
L20: {long x = VAL+1; INLINE[I]=MAP2[x];}
|
|
} /* end loop */
|
|
{long x = LNLENG+1; INLINE[x]=0;}
|
|
printf("%s\n",INLINE+1);
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define TYPE() fTYPE()
|
|
#undef MPINIT
|
|
void fMPINIT() {
|
|
long FIRST, I, J, LAST, VAL;
|
|
static long RUNS[7][2] = {32,34, 39,46, 65,90, 97,122, 37,37, 48,57, 0,126};
|
|
|
|
|
|
/* 10 */ for (I=1; I<=128; I++) {
|
|
L10: MAP1[I]= -1;
|
|
} /* end loop */
|
|
VAL=0;
|
|
/* 20 */ for (I=0; I<7; I++) {
|
|
FIRST=RUNS[I][0];
|
|
LAST=RUNS[I][1];
|
|
/* 22 */ for (J=FIRST; J<=LAST; J++) {
|
|
J++; if(MAP1[J] >= 0) goto L22;
|
|
MAP1[J]=VAL;
|
|
VAL=VAL+1;
|
|
L22: J--;
|
|
} /* end loop */
|
|
L20: /*etc*/ ;
|
|
} /* end loop */
|
|
MAP1[128]=MAP1[10];
|
|
/* FOR THIS VERSION, TAB (9) MAPS TO SPACE (32), SO DEL (127) USES TAB'S VALUE */
|
|
MAP1[10]=MAP1[33];
|
|
MAP1[11]=MAP1[33];
|
|
|
|
/* 30 */ for (I=0; I<=126; I++) {
|
|
I++; VAL=MAP1[I]+1; I--;
|
|
MAP2[VAL]=I*('B'-'A');
|
|
L30: if(I >= 64)MAP2[VAL]=(I-64)*('B'-'A')+'@';
|
|
} /* end loop */
|
|
|
|
return;
|
|
}
|
|
|
|
|
|
|
|
#define MPINIT() fMPINIT()
|
|
#undef SAVEIO
|
|
void fSAVEIO(OP,IN,ARR)long ARR[], IN, OP; {
|
|
static FILE *F; char NAME[50];
|
|
|
|
/* IF OP=0, ASK FOR A FILE NAME AND OPEN A FILE. (IF IN=.TRUE., THE FILE IS FOR
|
|
* INPUT, ELSE OUTPUT.) IF OP>0, READ/WRITE ARR FROM/INTO THE PREVIOUSLY-OPENED
|
|
* FILE. (ARR IS A 250-INTEGER ARRAY.) IF OP<0, FINISH READING/WRITING THE
|
|
* FILE. (FINISHING WRITING CAN BE A NO-OP IF A "STOP" STATEMENT DOES IT
|
|
* AUTOMATICALLY. FINISHING READING CAN BE A NO-OP AS LONG AS A SUBSEQUENT
|
|
* SAVEIO(0,.FALSE.,X) WILL STILL WORK.) IF YOU CAN CATCH ERRORS (E.G., NO SUCH
|
|
* FILE) AND TRY AGAIN, GREAT. DEC F40 CAN'T. */
|
|
|
|
|
|
{long ifvar; ifvar=(OP); switch (ifvar<0? -1 : ifvar>0? 1 : 0) { case -1:
|
|
goto L10; case 0: goto L20; case 1: goto L30; }}
|
|
|
|
L10: fclose(F);
|
|
return;
|
|
|
|
L20: printf("\nFile name: ");
|
|
IGNORE(fgets(NAME, sizeof(NAME), stdin));
|
|
F=fopen(NAME,(IN ? READ_MODE : WRITE_MODE));
|
|
if(F == NULL) {printf("Can't open file, try again.\n"); goto L20;}
|
|
return;
|
|
|
|
L30: if(IN)IGNORE(fread(ARR,4,250,F));
|
|
if(!IN)fwrite(ARR,4,250,F);
|
|
return;
|
|
|
|
}
|
|
|
|
|
|
|
|
long fIABS(N)long N; {return(N<0? -N : N);}
|
|
long fMOD(N,M)long N, M; {return(N%M);}
|